URI Problem 2623 Solution Categories with Various Products

URI Problem 2623 Solution Categories with Various Products - URI Online Judge Solution

URI Online Judge Solution 2623 Categories with Various Products Using PostgreSQL Query Language.

The sales industry needs a report to know what products are left in stock. To help the sales industry, display the product name and category name for products whose amount is greater than 100 and the category ID is 1,2,3,6 or 9. Show the results in ascendent order by category ID.

Schema

products
Column	Type
id (PK)	numeric
name	character varying (255)
amount	numeric
price	numeric
id_categories (FK)	numeric

categories
Column	Type
id (PK)	numeric
name	character varying (255)

Tables

products
id	name	amount	price	id_categories
1	Blue Chair	30	300.00	9
2	Red Chair	200	2150.00	2
3	Disney Wardrobe	400	829.50	4
4	Blue Toaster	20	9.90	3
5	Solar Panel	30	3000.25	4

categories
id	name
1	Superior
2	Super Luxury
3	Modern
4	Nerd
5	Infantile
6	Robust
9	Wood

Output Sample

name	name
Red Chair	Super Luxury

URI 2623 Solution in SQL:


SELECT products.name, categories.name
FROM products
INNER JOIN categories 
ON products.id_categories = categories.id
WHERE products.amount > 100 
  AND products.id_categories IN (1,2,3,6,9)

Comments

URI Problem 1001 Solution Extremely Basic - - URI Online Judge Solution

URI Online Judge Problem 1001 Extremely Basic Solution using C, Python Programming Language. Read 2 variables, named A and B and make the sum of these two variables, assigning its result to the variable X . Print X as shown below. Print endline after the result otherwise you will get “ Presentation Error ”. Input The input file will contain 2 integer numbers. Output Print the letter X (uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the endline after all. Samples Input Samples Output 10 9 X = 19 -10 4 X = -6 15 -7 X = 8 URI 1001 Solution in Python A = int(input()) B = int(input()) X = A + B print("X =",X); URI 1001 Solution in C: #include int main() { int A,B,X; scanf ("%d %d", &A, &B); X=A+B; printf("X = %d\n",X); return 0; }

URI Online Judge Solution 1151 Easy Fibonacci

URI Online Judge Solution 1151 Easy Fibonacci using C Programming Language. he following sequence of numbers 0 1 1 2 3 5 8 13 21 ... is known as the Fibonacci Sequence. Thereafter, each number after the first 2 is equal to the sum of the previous two numbers. Write an algorithm that reads an integer N (N < 46) and that print the first N numbers of this sequence. Input The input file contains an integer number N (0 < N < 46). Output The numbers should be printed on the same line, separated by a blank space. There is no space after the last number. Thanks to Cássio F. Input Sample Output Sample 5 0 1 1 2 3 Solution using C : #include <stdio.h> int main() { int n,i,n1,n2,t; scanf("%d",&n); for(i=1; i<=n; i++) { if(i==1) { n1 = 0; printf("%d",n1); } else if(i==2) { n2 = 1; printf("%d",n2); }

URI Online Judge Solution 1149 Summing Consecutive Integers

URI Online Judge Solution 1149 Summing Consecutive Integers using C Programming Language. Write an algorithm to read a value A and a value N. Print the sum of N numbers from A (inclusive). While N is negative or ZERO, a new N (only N) must be read. All input values are in the same line. Input The input contains only integer values, can be positive or negative. Output The output contains only an integer value. Input Sample Output Sample 3 2 7 3 -1 0 -2 2 7 Solution using C : #include <stdio.h> int main() { int a,n,s=0; scanf("%d%d",&a,&n); while(n<=0) scanf("%d",&n); while(n) { s += a++; n--; } printf("%d\n",s); return 0; }

URI Online Judge Solution

Search This Blog