URI Problem 1924 Solution Vitória and Her Indecision

URI Problem 1924 Solution Vitória and Her Indecision - URI Online Judge Solution

URI Online Judge Solution 1924 Vitória and Her Indecision Using Python Programming Language.

There’s no one in the world more indecisive than Vitória. Despite the fact that she knows she’s a great programmer, like one of the that have a lot of projects in IT field published and many others being written, she’s not sure if she’s going to be a professional programmer. There are nights that she wants to study Computer Science (Ciência da Computação, in portuguese), there are days she wants to study some Engineering, some days she even talks about taking some Humanities course, what a sin! But you can help her do the right choice. Your task is simple, It’ll be given a list with the bachelor courses that Vitória is in doubt, the output should be the course she must choose.

Input

The first line of the input is an integer 1 ≤ n ≤ 2000, representing the number of courses that must be considered. Each of the next n lines, there is a course S, 1 ≤ |S| ≤ 100, the name of one of the courses Vitória is in the doubt.

Output
Print the name of the course Vitória must take in portuguese without accentuation.

Input Samples	Output Samples
3 Ciencia da Computacao Engenharia Eletrica Matematica	Ciencia da Computacao

Input Samples

Output Samples

3
Ciencia da Computacao
Engenharia Eletrica
Matematica
Ciencia da Computacao

3 Sociologia Filosofia Fisica	Ciencia da Computacao

3
Sociologia
Filosofia
Fisica
Ciencia da Computacao

Solution Using Python:

T = int(input())
while T>0:
    S = input()
    T-=1
print("Ciencia da Computacao")

Comments

URI Problem 1001 Solution Extremely Basic - - URI Online Judge Solution

URI Online Judge Problem 1001 Extremely Basic Solution using C, Python Programming Language. Read 2 variables, named A and B and make the sum of these two variables, assigning its result to the variable X . Print X as shown below. Print endline after the result otherwise you will get “ Presentation Error ”. Input The input file will contain 2 integer numbers. Output Print the letter X (uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the endline after all. Samples Input Samples Output 10 9 X = 19 -10 4 X = -6 15 -7 X = 8 URI 1001 Solution in Python A = int(input()) B = int(input()) X = A + B print("X =",X); URI 1001 Solution in C: #include int main() { int A,B,X; scanf ("%d %d", &A, &B); X=A+B; printf("X = %d\n",X); return 0; }

URI Online Judge Solution 1151 Easy Fibonacci

URI Online Judge Solution 1151 Easy Fibonacci using C Programming Language. he following sequence of numbers 0 1 1 2 3 5 8 13 21 ... is known as the Fibonacci Sequence. Thereafter, each number after the first 2 is equal to the sum of the previous two numbers. Write an algorithm that reads an integer N (N < 46) and that print the first N numbers of this sequence. Input The input file contains an integer number N (0 < N < 46). Output The numbers should be printed on the same line, separated by a blank space. There is no space after the last number. Thanks to Cássio F. Input Sample Output Sample 5 0 1 1 2 3 Solution using C : #include <stdio.h> int main() { int n,i,n1,n2,t; scanf("%d",&n); for(i=1; i<=n; i++) { if(i==1) { n1 = 0; printf("%d",n1); } else if(i==2) { n2 = 1; printf("%d",n2); }

URI Online Judge Solution 1149 Summing Consecutive Integers

URI Online Judge Solution 1149 Summing Consecutive Integers using C Programming Language. Write an algorithm to read a value A and a value N. Print the sum of N numbers from A (inclusive). While N is negative or ZERO, a new N (only N) must be read. All input values are in the same line. Input The input contains only integer values, can be positive or negative. Output The output contains only an integer value. Input Sample Output Sample 3 2 7 3 -1 0 -2 2 7 Solution using C : #include <stdio.h> int main() { int a,n,s=0; scanf("%d%d",&a,&n); while(n<=0) scanf("%d",&n); while(n) { s += a++; n--; } printf("%d\n",s); return 0; }

URI Online Judge Solution

Search This Blog