URI Problem 1179 Solution Array Fill IV - URI Online Judge Solution

URI Online Judge Solution 1179 Array Fill IV Using C, Python Programming Language.

In this problem you need to read 15 numbers and must put them into two different arrays: par if the number is even or impar if this number is odd. But the size of each of the two arrrays is only 5 positions. So every time you fill one of two arrays, you must print the entire array to be able to use it again for the next numbers that are read. At the end, all remaining numbers of each one of these two arrays must be printed beginning with the odd array. Each array can be filled how many times are necessary.

Input

The input contains 15 integer numbers.

Output

Print the output like the following example.

Input Sample	Output Sample
1 3 4 -4 2 3 8 2 5 -7 54 76 789 23 98	par[0] = 4 par[1] = -4 par[2] = 2 par[3] = 8 par[4] = 2 impar[0] = 1 impar[1] = 3 impar[2] = 3 impar[3] = 5 impar[4] = -7 impar[0] = 789 impar[1] = 23 par[0] = 54 par[1] = 76 par[2] = 98

Solution Using C:

#include <stdio.h>
int main()
{
int a,b,c=0,d,e,f,g,h,i,j,l=0,m=0,x=0,n,p,Even[5],Odd[5],List[15];
for(b=0; b<15; b++)
scanf("%d", &List[b]);
for(a=0; a<15; a++)
{
if(l==5)
{
for(n=0; n<5; n++)
printf("impar[%d] = %d\n", n, Odd[n]);
l=0;
}
if(m==5)
{
for(p=0; p<5; p++)
printf("par[%d] = %d\n", p, Even[p]);
m=0;
}
if(List[a]%2!=0)
{
Odd[c]=List[a];
++c;
l++;
if(c==5) c=0;
}
if(List[a]%2==0)
{
Even[x]=List[a];
++x;
m++;
if(x==5) x=0;
}
}
for(i=0; i<l; i++)
printf("impar[%d] = %d\n", i, Odd[i]);
for(j=0; j<m; j++)
printf("par[%d] = %d\n", j, Even[j]);
return 0;
}

Comments

URI Problem 1001 Solution Extremely Basic - - URI Online Judge Solution

URI Online Judge Problem 1001 Extremely Basic Solution using C, Python Programming Language. Read 2 variables, named A and B and make the sum of these two variables, assigning its result to the variable X . Print X as shown below. Print endline after the result otherwise you will get “ Presentation Error ”. Input The input file will contain 2 integer numbers. Output Print the letter X (uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the endline after all. Samples Input Samples Output 10 9 X = 19 -10 4 X = -6 15 -7 X = 8 URI 1001 Solution in Python A = int(input()) B = int(input()) X = A + B print("X =",X); URI 1001 Solution in C: #include int main() { int A,B,X; scanf ("%d %d", &A, &B); X=A+B; printf("X = %d\n",X); return 0; }

URI Online Judge Solution 1151 Easy Fibonacci

URI Online Judge Solution 1151 Easy Fibonacci using C Programming Language. he following sequence of numbers 0 1 1 2 3 5 8 13 21 ... is known as the Fibonacci Sequence. Thereafter, each number after the first 2 is equal to the sum of the previous two numbers. Write an algorithm that reads an integer N (N < 46) and that print the first N numbers of this sequence. Input The input file contains an integer number N (0 < N < 46). Output The numbers should be printed on the same line, separated by a blank space. There is no space after the last number. Thanks to Cássio F. Input Sample Output Sample 5 0 1 1 2 3 Solution using C : #include <stdio.h> int main() { int n,i,n1,n2,t; scanf("%d",&n); for(i=1; i<=n; i++) { if(i==1) { n1 = 0; printf("%d",n1); } else if(i==2) { n2 = 1; printf("%d",n2); }

URI Online Judge Solution 1149 Summing Consecutive Integers

URI Online Judge Solution 1149 Summing Consecutive Integers using C Programming Language. Write an algorithm to read a value A and a value N. Print the sum of N numbers from A (inclusive). While N is negative or ZERO, a new N (only N) must be read. All input values are in the same line. Input The input contains only integer values, can be positive or negative. Output The output contains only an integer value. Input Sample Output Sample 3 2 7 3 -1 0 -2 2 7 Solution using C : #include <stdio.h> int main() { int a,n,s=0; scanf("%d%d",&a,&n); while(n<=0) scanf("%d",&n); while(n) { s += a++; n--; } printf("%d\n",s); return 0; }

URI Online Judge Solution

Search This Blog