Skip to main content

URI Problem 1050 DDD Solution in C, Python - URI Online Judge Solution


URI Online Judge Solution 1050 DDD using C Programming Language.

Read an integer number that is the code number for phone dialing. Then, print the destination according to the following table:

If the input number isn’t found in the above table, the output must be:
DDD nao cadastrado
That means “DDD not found” in Portuguese language.
Input
The input consists in a unique integer number.
Output
Print the city name corresponding to the input DDD. Print DDD nao cadastrado if doesn't exist corresponding DDD to the typed number.
Input SampleOutput Sample
11
Sao Paulo

URI 1045 Solution in C :

#include <stdio.h>
int main() {
    int num;
    scanf("%d",&num);
    switch(num)
    {
    case 61:
        printf("Brasilia\n");
        break;
    case 71:
        printf("Salvador\n");
        break;
    case 11:
        printf("Sao Paulo\n");
        break;
    case 21:
        printf("Rio de Janeiro\n");
        break;
    case 32:
        printf("Juiz de Fora\n");
        break;
    case 19:
        printf("Campinas\n");
        break;
    case 27:
        printf("Vitoria\n");
        break;
    case 31:
        printf("Belo Horizonte\n");
        break;
    default:
        printf("DDD nao cadastrado\n");
    }
     return 0;
}

URI 1045 Solution in Python :

Comments

Popular posts from this blog

URI Problem 1001 Solution Extremely Basic - - URI Online Judge Solution

URI Online Judge Problem 1001 Extremely Basic Solution using C, Python Programming Language. Read 2 variables, named  A  and  B  and make the sum of these two variables, assigning its result to the variable  X . Print  X  as shown below. Print endline after the result otherwise you will get “ Presentation Error ”. Input The input file will contain 2 integer numbers. Output Print the letter  X  (uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the endline after all. Samples Input Samples Output 10 9 X = 19 -10 4 X = -6 15 -7 X = 8 URI 1001 Solution in Python A = int(input()) B = int(input()) X = A + B print("X =",X); URI 1001 Solution in C: #include int main() { int A,B,X; scanf ("%d %d", &A, &B); X=A+B; printf("X = %d\n",X); return 0; }

URI Problem 1179 Solution Array Fill IV - URI Online Judge Solution

URI Online Judge Solution 1179 Array Fill IV  Using C, Python Programming Language. In this problem you need to read 15 numbers and must put them into two different arrays: par if the number is even or impar if this number is odd. But  the size of each of the two arrrays is only 5 positions. So every time you fill one of two arrays, you must print the entire array to be able to use it again for the next numbers that are read. At the end, all remaining numbers of each one of these two arrays must be printed beginning with the odd array. Each array can be filled how many times are necessary. Input The input contains 15 integer numbers. Output Print the output like the following example. Input Sample Output Sample 1 3 4 -4 2 3 8 2 5 -7 54 76 789 23 98 par[0] = 4 par[1] = -4 par[2] = 2 par[3] = 8 par[4] = 2 impar[0] = 1 impar[1] = 3 impar[2] = 3 impar[3] = 5 impar[4] = -7 impar[0] = 789 impar[1] = 23 par[0] = 54 par[1] = 76 par[2] = 98 Solution Using C: #include <stdi...

URI Problem 1186 Solution Below the Secundary Diagonal - URI Online Judge Solution

URI Online Judge Solution 1186 Below the Secundary Diagonal   Using C, Python Programming Language. Read an uppercase character that indicates an operation that will be performed in an array M[12][12]. Then, calculate and print the sum or average considering only that numbers that are below of the Secundary diagonal of the array, like shown in the following figure (green area). Input The first line of the input contains a single uppercase character O ('S' or 'M'), indicating the operation Sum or Average (Média in portuguese) to be performed with the elements of the array. Follow 144 floating-point numbers of the array. Output Print the calculated result (sum or average), with one digit after the decimal point. Input Sample Output Sample S 5.0 0.0 -3.5 2.5 4.1 ... 12.6 Solution Using C: #include <stdio.h> int main() {     double a=0.0, M[12][12];     char T[2];     int x,y,c=0;     scanf("%s", &T);     for(x=0;x<=1...