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URI Online Judge Solution 1118 Several Scores with Validation


URI Online Judge Solution 1118 Several Scores with Validation using C Programming Language.
Write an program to read two scores of a student. Calculate and print the semester average. The program must accept only valid scores (a score must fit in the range [0.10]). Each score must be validated separately.
The program must print a message "novo calculo (1-sim 2-nao)" that means "new calculate (1-yes 2-no)". After, the input will be (1 or 2). 1 means a new calculation, 2 means that the execution must be finished.

Input

The input file contains several positive or negative floating-point (double) values​. After the input of 2 valid scores, an integer number X will be read. Your program must stop when X = 2.

Output

If an invalid score is read, must be printed the message "nota invalida". When two valid scores are read, the message "media = " must be printed folowed by the average between these 2 scores. The message "novo calculo (1-sim 2-nao)" must be printed after reading X. This message should be displayed again if the standard input number for X is less than 1 or greater than 2, as example below.
The output average must be printed with 2 digits after the decimal point.
Input SampleOutput Sample
-3.5
3.5
11.0
10.0
4
1
8.0
9.0
2
nota invalida
nota invalida
media = 6.75
novo calculo (1-sim 2-nao)
novo calculo (1-sim 2-nao)
media = 8.50
novo calculo (1-sim 2-nao)

Solution using C :

#include<stdio.h>
int main()
{
    float n,s,p,k;
    s = p = k = 0;
    while(1)
    {
        scanf("%f",&n);
        if(n < 0.0 || n > 10.0)
            printf("nota invalida\n");
        else
        {
            s += n;
            p++;
            if(p==2)
            {
                s/=2;
                printf("media = %.2lf\n",s);
                printf("novo calculo (1-sim 2-nao)\n");
                while(1)
                {
                    scanf("%f",&n);
                    if((int)n==1)
                    {
                        s = p = 0;
                        k=1;
                        break;
                    }
                    else if((int)n==2)
                        return 0;
                    else
                        printf("novo calculo (1-sim 2-nao)\n");
                }
            }
        }
    }
    return 0;
}
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