Skip to main content

URI Online Judge Solution 1118 Several Scores with Validation


URI Online Judge Solution 1118 Several Scores with Validation using C Programming Language.
Write an program to read two scores of a student. Calculate and print the semester average. The program must accept only valid scores (a score must fit in the range [0.10]). Each score must be validated separately.
The program must print a message "novo calculo (1-sim 2-nao)" that means "new calculate (1-yes 2-no)". After, the input will be (1 or 2). 1 means a new calculation, 2 means that the execution must be finished.

Input

The input file contains several positive or negative floating-point (double) values​. After the input of 2 valid scores, an integer number X will be read. Your program must stop when X = 2.

Output

If an invalid score is read, must be printed the message "nota invalida". When two valid scores are read, the message "media = " must be printed folowed by the average between these 2 scores. The message "novo calculo (1-sim 2-nao)" must be printed after reading X. This message should be displayed again if the standard input number for X is less than 1 or greater than 2, as example below.
The output average must be printed with 2 digits after the decimal point.
Input SampleOutput Sample
-3.5
3.5
11.0
10.0
4
1
8.0
9.0
2
nota invalida
nota invalida
media = 6.75
novo calculo (1-sim 2-nao)
novo calculo (1-sim 2-nao)
media = 8.50
novo calculo (1-sim 2-nao)

Solution using C :

#include<stdio.h>
int main()
{
    float n,s,p,k;
    s = p = k = 0;
    while(1)
    {
        scanf("%f",&n);
        if(n < 0.0 || n > 10.0)
            printf("nota invalida\n");
        else
        {
            s += n;
            p++;
            if(p==2)
            {
                s/=2;
                printf("media = %.2lf\n",s);
                printf("novo calculo (1-sim 2-nao)\n");
                while(1)
                {
                    scanf("%f",&n);
                    if((int)n==1)
                    {
                        s = p = 0;
                        k=1;
                        break;
                    }
                    else if((int)n==2)
                        return 0;
                    else
                        printf("novo calculo (1-sim 2-nao)\n");
                }
            }
        }
    }
    return 0;
}
Labels:

Comments

Post a Comment

Popular posts from this blog

URI Problem 1001 Solution Extremely Basic - - URI Online Judge Solution

URI Online Judge Problem 1001 Extremely Basic Solution using C, Python Programming Language. Read 2 variables, named  A  and  B  and make the sum of these two variables, assigning its result to the variable  X . Print  X  as shown below. Print endline after the result otherwise you will get “ Presentation Error ”. Input The input file will contain 2 integer numbers. Output Print the letter  X  (uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the endline after all. Samples Input Samples Output 10 9 X = 19 -10 4 X = -6 15 -7 X = 8 URI 1001 Solution in Python A = int(input()) B = int(input()) X = A + B print("X =",X); URI 1001 Solution in C: #include int main() { int A,B,X; scanf ("%d %d", &A, &B); X=A+B; printf("X = %d\n",X); return 0; }
Post a Comment
Read more

URI Online Judge Solution 1151 Easy Fibonacci

URI Online Judge Solution 1151 Easy Fibonacci using C Programming Language. he following sequence of numbers 0 1 1 2 3 5 8 13 21 ... is known as the Fibonacci Sequence. Thereafter, each number after the first 2 is equal to the sum of the previous two numbers. Write an algorithm that reads an integer N (N < 46) and that print the first N numbers of this sequence. Input The input file contains an integer number N (0 < N < 46). Output The numbers ​​should be printed on the same line, separated by a blank space. There is no space after the last number. Thanks to Cássio F. Input Sample Output Sample 5 0 1 1 2 3 Solution using C : #include <stdio.h> int main() {     int n,i,n1,n2,t;     scanf("%d",&n);     for(i=1; i<=n; i++)     {         if(i==1)         {         ...
Post a Comment
Read more

URI Problem 1186 Solution Below the Secundary Diagonal - URI Online Judge Solution

URI Online Judge Solution 1186 Below the Secundary Diagonal   Using C, Python Programming Language. Read an uppercase character that indicates an operation that will be performed in an array M[12][12]. Then, calculate and print the sum or average considering only that numbers that are below of the Secundary diagonal of the array, like shown in the following figure (green area). Input The first line of the input contains a single uppercase character O ('S' or 'M'), indicating the operation Sum or Average (Média in portuguese) to be performed with the elements of the array. Follow 144 floating-point numbers of the array. Output Print the calculated result (sum or average), with one digit after the decimal point. Input Sample Output Sample S 5.0 0.0 -3.5 2.5 4.1 ... 12.6 Solution Using C: #include <stdio.h> int main() {     double a=0.0, M[12][12];     char T[2];     int x,y,c=0;     scanf("%s", &T);     for(x=0;x<=1...
Post a Comment
Read more